The Amcat Automata Fix section is a critical part of the recruitment process for several companies like Cognizant and Wipro. It assesses a candidate’s ability to debug erroneous code and fix it efficiently. This article provides insights into the Amcat Automata Fix test pattern, common types of questions, solutions, and preparation tips.
In the Amcat Automata Fix section, candidates can choose their preferred programming language: C, C++, or Java. This section consists of three primary types of questions:
Candidates are required to fix logical errors in the given code. Topics like looping, conditions, and algorithm logic are commonly tested.
These questions involve correcting syntax errors without altering the program’s logic. The test cases and logic will be provided in the question itself.
This is the most challenging question type. Candidates need to complete a partially written program by reusing existing functions or classes. A “helper code tab” is provided to view reusable components.
Key Instructions:
main()
function unless explicitly required.Problem:
#include n
int main()
{
float x = 1.1;
switch (x)
{
case 1: printf("Choice is 1");
break;
default: printf("Invalid choice");
break;
}
return 0;
}
Solution:
#include <stdio.h>
int main()
{
int x = 1;
switch (x)
{
case 1: printf("Choice is 1");
break;
default: printf("Invalid choice");
break;
}
return 0;
}
Explanation:
switch
statement must be an integral type (e.g., int
, char
, or enum
). The variable x
was changed to int
.Problem:
void main() {
int i, j, n = 5;
for(i = 1; i < n; i++)
{
for(j = i; j < n; j++);
{
printf("%d", i);
}
printf("\n");
}
}
Solution:
void main() {
int i, j, n = 5;
for(i = 1; i < n; i++)
{
for(j = i; j < n; j++)
{
printf("%d", i);
}
printf("\n");
}
}
Explanation:
;
) after the inner for
loop caused it to execute only once. Removing it ensures the loop iterates as intended.Problem: Find the index of the equilibrium element in an array. An equilibrium element is one where the sum of all elements on its left equals the sum on its right.
Example: For array a[] = {1, 2, 3, 4, 3, 3}
, the equilibrium element is 4
because 1 + 2 + 3 = 3 + 3
.
Code Template:
#include <stdio.h>
int left_side_sum(int a[], int n, int idx);
int right_side_sum(int a[], int n, int idx);
int findEquilibriumIndex(int a[], int n);
int main() {
int a[10], n, i;
scanf("%d", &n);
for(i = 0; i < n; i++) {
scanf("%d", &a[i]);
}
int equiIndex = findEquilibriumIndex(a, n);
if(equiIndex != -1) {
printf("%d", a[equiIndex]);
}
return 0;
}
Solution:
int left_side_sum(int a[], int n, int idx) {
int sum = 0;
for(int i = 0; i < idx; i++) {
sum += a[i];
}
return sum;
}
int right_side_sum(int a[], int n, int idx) {
int sum = 0;
for(int i = idx + 1; i < n; i++) {
sum += a[i];
}
return sum;
}
int findEquilibriumIndex(int a[], int n) {
for(int i = 0; i < n; i++) {
if(left_side_sum(a, n, i) == right_side_sum(a, n, i)) {
return i;
}
}
return -1;
}
Explanation:
left_side_sum
and right_side_sum
calculate the sums on either side of the index.Conclusion
AMCAT Automata Fix is a crucial section for coding assessments, testing your debugging and problem-solving skills. To excel, focus on understanding common coding errors, logic optimization, and time complexity. Practice frequently with previously asked questions, analyze test cases, and refine your debugging approach.
.