Mphasis Aptitude Questions are asked to test a candidate’s conceptual understanding of aptitude questions, problem-solving capability, and business understanding. Also, Mphasis aptitude questions are quite easy to solve compared to other sections.
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Mphasis uses AMCAT as its assessment platform for conducting the Aptitude Round. The first step to take as a candidate aspiring to join Mphasis is to get familiar with the syllabus and question types in AMCAT.
AMCAT is one of the easiest exams when it comes to Aptitude Questions. They are intended to test your basic understanding ability and concepts.
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The difficulty of Mphasis Aptitude Questions is categorized under following types based on the level of difficulty.
One should try to solve easy questions in less than 30 seconds. This will help in saving more time for intermediate level questions. For intermediate level questions, 45 seconds to 1 minute is the ideal time to solve questions.
Know more about Mphasis Recruitment Process and Test Pattern here.
Try to solve the following Mphasis Aptitude Questions in under a minute.
1. In how many ways can the 7 letters A, B, C, D, E, F, and G be arranged so that C and E never together.
Ans: 3600
C and E never together = Total arrangements C and E together, Total arrangements are 7! C and E together = pack c and e into one unit + 5 other alphabets = 6! 2!, (2! is to arrange c and e internally), C and E never together = Total arrangements C and E together = 7! 6! 2! = 3600
2. A can do a piece of work in 8 days and B can do the same work in 6 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C?
Ans: d
C’s 1 day’s work = 1/3 – (1/8 + 1/6 ) = 1/3 – 7/24 = 1/24A’s wages : B’s wages : C’s wages = 1/8 : 1/6 : 1/24 = 3 : 4 : 1C’s share (for 3 days) = Rs. ( 3 * 1/24 * 3200) = Rs. 400.
3. In how many ways can the letters of the word ‘MANAGE’ be arranged?
Ans: a
The word ‘MANAGE’ contains 6 letters, namely 1M, 2A, 1N, 1G and 1N.The required number of ways = 6! /2! = 360
4. If log a/b + log b/a = log (a + b), then
Ans: a
According to formulae: log a/b + log b/a = log a+b,log a+b = log (a/b * b/a) = log 1, Hence, a + b = 1.
5. The H.C.F. of two numbers is 30 and the other two factors of their L.C.M. are 10 and 12. The larger of the two numbers is:
Ans: c
Clearly, the numbers are (30 x 10) and (30 x 12).Larger number = (30 x 12) = 360.
6. If a number is exactly divisible by 85, then what will be the remainder when the same number is divided by 17?
Ans: d
85 is a multiple of 17 (i.e., 17 x 5 = 85), any number which is divisible by 85 will also be divisible by 17.
7. In how many ways can a number 6084 be written as a product of two different factors?
Ans: b
Factorizing 6084: = 2^2 x 3^2 x 13^2If N = a^p b^q c^r, where a,b,c are primes, Number of factors is represented by :(p+1)(q+1)(r+1) => (2+1)(2+1)(2+1) = 27Number of Ordered pairs of any two factors is ( 27 + 1)/2 = 14Since 6084 is a perfect square, evidently the ordered pair (78,78) is also counted in the above 14 pairs. So, the number of ways in which 6084 can be expressed as a product of two different factors is 13.
8. A rectangular courtyard 3.78 meters long 5.25 meters wide is to be paved exactly with square tiles, all of the same sizes. what is the largest size of the tile which could be used for the purpose?
Ans: c
3.78 meters =378 cm = 2 3 3 3 75.25 meters=525 cm = 5 5 3 7The common factors are 3 and 7, therefore the LCM = 3 7 = 21Hence the largest size of square tiles that can be paved exactly with square tiles is 21 cm.
9. A boat can travel at a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 68 km downstream.
Ans: c
Speed downstream = (13 + 4) km/hr = 17 km/hr.Time taken to travel 68 km downstream = (68/ 17) hrs = 4 hrs.
10. An article was sold for Rs. 2770. Had it been sold for Rs. 3000 there would have been an additional gain of 10%. Cost Price of the article is:
Ans: a
Original CP = Rs. X, New profit = (3000 x) Rs.New profit % = (3000 x)*100/CP, (300000 100x)/CP (277000 + 100x)/CP = 1023000/CP = 10, 10CP = 23000, CP = 23000/10, CP = 2300The original Cost price is Rs. 2300
Since Mphasis follows AMCAT assessment platform, try solving more of AMCAT Aptitude Questions to gain better exposure in solving Mphasis aptitude questions.
Some of the shortcuts and tips are discussed in the following topics