#include <stdio.h>
void findDuplicates(int arr[], int n) {
printf("Repeating elements are:\n");
for (int i = 0; i < n; i++) {
for (int j = i + 1; j < n; j++) {
if (arr[i] == arr[j]) {
printf("%d\n", arr[i]);
break;
}
}
}
}
int main() {
int arr[] = {1, 2, 3, 4, 2, 3, 5};
int n = sizeof(arr) / sizeof(arr[0]);
findDuplicates(arr, n);
return 0;
}
[1, 2, 3, 4, 2, 3, 5]
Output:Repeating elements are:
2
3
#include <iostream>
using namespace std;
void findDuplicates(int arr[], int n) {
cout << "Repeating elements are:\n";
for (int i = 0; i < n; i++) {
for (int j = i + 1; j < n; j++) {
if (arr[i] == arr[j]) {
cout << arr[i] << endl;
break;
}
}
}
}
int main() {
int arr[] = {1, 2, 3, 4, 2, 3, 5};
int n = sizeof(arr) / sizeof(arr[0]);
findDuplicates(arr, n);
return 0;
}
[1, 2, 3, 4, 2, 3, 5]
Output:Repeating elements are:
2
3